author=Room3327 link=topic=1585.msg69263#msg69263 date=1534555614]
I'm not mocking you Brad,
I was not referring to you room.
for the most part you are right,
Which part is wrong?.
I was trying to simplify it for others. Yes the emf across a coil reverses with BEMF and the current continues in the same direction it was going.
No,no it dose not.
BEMF is of the same polarity to that of the applied EMF
BEMF is the self generated EMF within an electric motor.
Once again,BEMF is being mixed up with inductive kickback.
The counter EMF is in reverse to the applied EMF,
Once again,that is wrong.
The CEMF is of the same polarity to that of the applied EMF--just like BEMF is of the same polarity to that of the applied EMF in an electric motor.
, and the CEMF is the reverse polarity of the applied EMF, I think your wrong there.
I am not wrong.
Both BEMF and CEMF are of the same polarity to that of the applied EMF.
When you drop a voltage across an inductor,what happens?
Why is there very little current flow through that inductor at T=0 to the first time constant?.
If the polarity produced by the CEMF or BEMF was opposite to that of the applied EMF,what would be the value of current flow at T=0 to the first time constant?
Get your self two 12 volt batteries,and hook them up reverse polarity to each other,and see what happens-how much current flow is there at the connection points?.
Then get 1 battery with say 12.6volts across it(the EMF),and one with say 12.2 volts across it(the CEMF),hook them up so as the polarity is the same(parallel),and then measure what the current flow is between them?.
My guess is you will get smoke in one test,and very little current flow in the other test.
the applied EMF is delayed from reaching it's maximum value across the inductor until the CEMF is over or the rise in current has stopped as far as I know
EMF denotes voltage,where voltage is the value of that EMF.
When you drop a voltage across an inductor,there is no delay to that voltage reaching it's maximum value,as you just dropped that voltage across the inductor.
The voltage across the inductor will always be the value you dropped across it,providing the source and connecting wires are able to handle the maximum current flow through that inductor without voltage drop.
The value of the CEMF has nothing to do with the voltage across the inductor,only the current flowing through the inductor.
If the connecting wires or source cannot maintain the voltage across the coil as the current rises,then the opposite to what you stated above is true,where the maximum voltage will appear across the coil at T=0,and then drop off as the CEMF reduces-->current rises. But this is only due to either the source or connecting wires being unable to handle the maximum current flow through the coil.
I am merely trying to educate some of those that do not understand this stuff without confusing them even more,
It would seem that the teachers need to go back to school them self,as those teachers seem to be the cause of the confusion.
I wasn't disagreeing with you,
It would seem that you are.
Brad
Never let your schooling get in the way of your education.