As requested. Copy and paste of Les Banki's post from OU.C.
I have been monitoring this thread from start.
Here is what I see:
The 'Akula0083 circuit' you are trying to duplicate is essentially a simple device which
(for simplicity), can be divided into two (2) sections:
a. Control (“exciter”)
b. “Free energy”
I comment mainly on the control section which you have thoroughly messed up!
Admit it or not, most of you have contributed to this.
I am particularly critical of some of the 'technical' comments made!
They are WAY OFF!
The control section is based on the TL494 PWM IC which has been around for over 30 years.
It became an industry standard, so to speak.
In the past, most computer SMPS used this IC.
It is well understood and works well.
If you care to watch (and pay attention!) to the video where Akula explains all three (3) versions of his MOSFET drivers, you would not be confused and would stop 'butchering' the circuit!
For example, arguments are still raging about that Ground wire connection to pin 16 of TL494.
If you remove that connection (like I have seen in some diagrams in this thread), you will also lose the Ground connection to the indicator LED HL11 AND the Ground connection to voltage divider R9-R11-R10 which will result in error amplifier A1+ (pin 1) will be at the supply voltage (+12V) potential trough R9 and part of R11 (pot)!
This has already been pointed out by one poster ('lost_bro' on page 6) and yet, even as I write this, yet another diagram appeared (“Akmodedit.png”) where that Ground connection is MISSING!
This diagram has been REPEATEDLY posted!
In other words:
By removing that Ground connection in the diagram, you DISABLE not only the indicator LED but also DISABLE BOTH error amplifiers, A1 & A2!
If you pay proper attention to the details in this video: http://www.youtube.com/watch
you will see that the disputed Ground link (connection) is PRESENT in all 3 versions of the diagram.
No, you don't even have to understand the language!
By the way, the author announced a few days ago that English subtitles are coming soon!
Then there is one other point which everyone have missed, including Akula it seems!
Irrespective of which (of the 3) MOSFET drivers you use, there is only ONE MOSFET in this device and the drive is single-ended.
Yet, the output logic control (pin13) is tied to pin 14 which is the reference voltage. (+5V, ±5%)
Therefore, the output stage is operating in push-pull mode.
(Only one poster commented on this, in RED, written over the diagram.)
Sure, it still works this way BUT the output frequency is only HALF the oscillator frequency.
If pin 13 was connected to Ground (0V), the output would operate in the single-ended mode which gives the option to parallel the two output transistors, thus gaining significant current drive to the MOSFET, either directly or through the complementary NPN/PNP driver, or through the dedicated Mosfet driver IC (IXDD609 or similar).
Lowest rise/fall times are achieved with dedicated Mosfet drivers (they are MOSFET based).
However, unless I need super fast switching, I prefer the complementary npn/pnp driver since I found that the MOSFET drivers are too “touchy” for experimental work (meaning they are too easy to blow up!).
To those who intend to try to duplicate this circuit, my advice is:
Make sure the control section works properly before attempting to experiment with the free energy section (which the transformer is part of).
Also, don't fall for all that nonsense (yes, nonsense!) about input/output power measurements as some posters promote!
Why do I make such a statement?
You are NOT dealing with a device with a claim of marginal OU in the order of a few percent which could perhaps be a measurement error!
If you want to know the input power to this device, I can give it to you right now:
The TL494 IC, running on a 15V supply has a maximum current draw of 10 mA.
(average 7.5 mA)
That translates to 150 mW (0.15 W). (maximum)
Add the 12V regulator's power consumption of approx. 96 mW (maximum) and you have a
TOTAL of 246 mW (0.246 W)
Now, just for the hell of it, DOUBLE it and round it to 0.5 W.
However, this device will produce 30 W (or more) depending on the LOAD and the transformer
I hope you can see the stupidity of those who blindly INSIST on input/output measurements!
Don't get me wrong.
Sure, you will be curious (as you should be!) about the output power of your device!
With devices like these, you may face a very different kind of problem!
Avalanche. Yes, avalanche.
I hope you know what that is.
(It is a runaway condition which, if not controlled, can cause DESTRUCTION of great magnitude.)
Don't believe it?
Fine. But don't complain if something blows up in your face! (or worse)
Oh...'MenofFather' posted suggestions to the winding method, including SHORTED turns!
Guys, with all due respect, with that kind of suggestions you will never get anywhere!