I am so surprised that nobody has said anything, I really am!!!!
Do you realise that it does not matter what high value the external capacitor is across the A/B plates, APART from the energy stored in A/B, with 4uF the energy is 2 joules, with 20uF it is 10 joules. This energy is put into there when there is a discharge into A plate and the switch is closed so the B plate goes to the ground.
The next discharge into A does not have the switch to ground, but there is via bb1 and C2. The question is what happens to that energy on A/B when the C1 capacitor has suddenly become 290pF.
Here is the charge for C2, this second discharge is short, controlling the C2 charge, until the first charge cycle starts again.
For those with the full correct circuit will now see how this all works.
Regards
Mike
---------------------------
"All truth passes through three stages. First, it is ridiculed, second it is violently opposed, and third, it is accepted as self-evident." Arthur Schopenhauer, Philosopher, 1788-1860
As a general rule, the most successful person in life is the person that has the best information.
|