Reducing the losses gets you closer to unity but not over it.
It doesn't mean that. It only means that you cannot analyze inductors with emf (voltage) as the current-causing agent, in all cases, because inductors only care about current.
Conversely, capacitors care only about voltage.
That why in order to preserve the energy stored in an inductor, you must close it and and to preserve the energy stored in a capacitor you must open it.
That's how religions work - not science. I don't accept anything without proof.
So, capacitance of the system don’t play any role in your opinion ? Nor dielectric layers in coils ? Is the apparent negative resistance part of the religious beliefs that you are so keen to dismiss ?
I really don’t understand why you don’t want to see to relationship between length of wire, frequency, impedance and capacitance for such a system ?
In my opinion length of wire which must be multiple of 1/2 wave length for the frequency of voltage injected into the system is of essence and the higher you go with frequency the higher accuracy is needed for length of wires used.
High frequency will remove most of the ohmic resistance in copper wires reducing the loss and this lead to load having always higher resistance than circuit providing electricity and this must be at least 10 times bigger, so a voltage dependant resistor can be employed as well for final adjustment.
Capacitance of the system must be calculated for desired output and can be quite high if a heavy load is to be powered.
I am pretty sure you already have sufficient knowledge but for those who are looking for a realationship this might be very useful
https://electronicsclub.info/impedance.htm#reactance Four electrical quantities determine the impedance (Z) of a circuit: resistance (R), capacitance (C), inductance (L) and frequency (f).
Square wave should be employed for signal generator.
To have such a generator working someone need to use reactance or parametric excitation.
In order not to draw excessive power from the source secondary coil(s) should have only 1 output wire connected not both. Watch youtube video above where Joel Lagace explains why. And I already mention this long time ago, but probably my lacking skills for explanation where at fault.
“It is so simple that you will laugh” … how difficult might be to hide a fake connection ? Or to pretend that all wires are connected ?
Open circuit or short circuit, choose one of the methods not both in the same device and work your way.
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Topic: Tariel Kapanadze's devices: How they might be faked (Read 44714 times)
