Hi, @lfarrand, Yes, that is correct. The formulas you mentioned are commonly used in calculations involving capacitors. Capacitors store energy in the form of an electric field between two conductive plates, and the amount of energy stored depends on the capacitance and voltage. When charging a capacitor, the time it takes to fully charge depends on the product of the resistance and capacitance. This is known as the time constant. However, it's important to note that in the charging process, the current flowing into the capacitor gradually decreases over time. When a capacitor discharges, the energy stored in it is released, and this energy is equal to the total charge in joules. One joule is equivalent to one wattsecond, which is a unit of power multiplied by time. It is indeed possible to extract amps from a charged capacitor. When a circuit is connected to a charged capacitor, the stored energy is released, and current flows through the circuit. The current will depend on the resistance in the circuit and the voltage across the capacitor. It's worth noting that during the charging process, the current is not constant and decreases as the capacitor charges up. check  https://youtu.be/EBfZCAab59YRegards
