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Author Topic: Spice term and its meaning  (Read 4392 times)
Group: Guest
Hey all:
   I have been getting into 3 phase line and motor systems lately and ran into a spice model that has a column labeled
Fourier component  and  Normalized component. I take these as the voltage/current measured in that point in the
circuit but need to know for sure. Thanks

thay
   

Group: Administrator
Hero Member
*****

Posts: 2905
It's not as complicated as it may seem...
Thay,

Could you be more specific about which model and spice program you are using?

Also, please clarify where you are seeing these columns and values.

.99
   
Group: Guest
   Here is the program and its output.
Y-Y source/load (no neutral) with harmonics                                             
*       
* phase1 voltage source and r (120 v /_ 0 deg) 
vsource1 1 0 sin(0 120 60 0 0) 
rsource1 1 2 1 
*       
* phase2 voltage source and r (120 v /_ 120 deg)
vsource2 3 0 sin(0 120 60 5.55555m 0)   
rsource2 3 4 1 
*       
* phase3 voltage source and r (120 v /_ 240 deg)
vsource3 5 0 sin(0 120 60 11.1111m 0)   
rsource3 5 6 1 
*       
* line resistances     
rline1 2 8 1   
rline2 4 9 1   
rline3 6 10 1   
*       
* phase 1 of load       
rload1 8 7 1k   
i3har1 8 7 sin(0 50m 180 0 0)   
i5har1 8 7 sin(0 50m 300 0 0)   
i7har1 8 7 sin(0 50m 420 0 0)   
i9har1 8 7 sin(0 50m 540 0 0)   
*       
* phase 2 of load       
rload2 9 7 1k   
i3har2 9 7 sin(0 50m 180 5.55555m 0)   
i5har2 9 7 sin(0 50m 300 5.55555m 0)   
i7har2 9 7 sin(0 50m 420 5.55555m 0)   
i9har2 9 7 sin(0 50m 540 5.55555m 0)   
*       
* phase 3 of load       
rload3 10 7 1k 
i3har3 10 7 sin(0 50m 180 11.1111m 0)   
i5har3 10 7 sin(0 50m 300 11.1111m 0)   
i7har3 10 7 sin(0 50m 420 11.1111m 0)   
i9har3 10 7 sin(0 50m 540 11.1111m 0)   
*       
* analysis stuff
.options itl5=0
.tran 0.5m 100m 12m 1u 
.plot tran v(2,8)       
.four 60 v(2,8)
.plot tran v(0,7)       
.four 60 v(0,7)
.plot tran v(8,7)       
.four 60 v(8,7)
.end   

Fourier analysis of line current:

Fourier components of transient response v(2,8) 
dc component =   5.423E-11
harmonic  frequency  Fourier    normalized    phase    normalized
no         (hz)     component    component    (deg)    phase (deg)
1      6.000E+01   1.198E-01     1.000000     0.000       0.000
2      1.200E+02   2.388E-10     0.000000   158.016     158.016
3      1.800E+02   3.136E-07     0.000003   -90.009     -90.009
4      2.400E+02   5.963E-11     0.000000  -111.510    -111.510
5      3.000E+02   4.990E-02     0.416665     0.000       0.000
6      3.600E+02   8.606E-11     0.000000  -124.565    -124.565
7      4.200E+02   4.990E-02     0.416668     0.000       0.000
8      4.800E+02   8.126E-11     0.000000  -159.638    -159.638
9      5.400E+02   9.406E-07     0.000008   -90.005     -90.005
total harmonic distortion =     58.925539  percent

Fourier analysis of voltage between the two “Y” center-points:

Fourier components of transient response v(0,7) 
dc component =   6.093E-08
harmonic  frequency  Fourier    normalized    phase    normalized
no         (hz)     component    component    (deg)    phase (deg)
1      6.000E+01   1.453E-04     1.000000    60.018       0.000
2      1.200E+02   6.263E-08     0.000431    91.206      31.188
3      1.800E+02   5.000E+01  344147.7879  -180.000    -240.018
4      2.400E+02   4.210E-07     0.002898   -21.103     -81.121
5      3.000E+02   3.023E-04     2.080596   119.981      59.963
6      3.600E+02   1.138E-07     0.000783    15.882     -44.136
7      4.200E+02   4.234E-04     2.913955    59.993      -0.025
8      4.800E+02   2.001E-07     0.001378    35.584     -24.434
9      5.400E+02   5.000E+01  344147.4728  -179.999    -240.017
total harmonic distortion =  ************  percent

Fourier analysis of load phase voltage:

Fourier components of transient response v(8,7) 
dc component =   6.070E-08
harmonic  frequency  Fourier    normalized    phase    normalized
no         (hz)     component    component    (deg)    phase (deg)
1      6.000E+01   1.198E+02     1.000000     0.000       0.000
2      1.200E+02   6.231E-08     0.000000    90.473      90.473
3      1.800E+02   5.000E+01     0.417500  -180.000    -180.000
4      2.400E+02   4.278E-07     0.000000   -19.747     -19.747
5      3.000E+02   9.995E-02     0.000835   179.850     179.850
6      3.600E+02   1.023E-07     0.000000    13.485      13.485
7      4.200E+02   9.959E-02     0.000832   179.790     179.789
8      4.800E+02   1.991E-07     0.000000    35.462      35.462
9      5.400E+02   5.000E+01     0.417499  -179.999    -179.999
total harmonic distortion =     59.043467  percent





I understand all except the fourier component and standardized component. Is this in volts or
amps. Then it could also be the reading across a 1 ohm resistor which would make it amps. In
the last output lines 3,9 both have 5.000e+1 which makes 50 in this case. That means to me
that the output on that phase for each of these harmonics is 50v which is bad

Just confirm or not will do it. Just new to this area specially with spice, never have used it.

thay
   

Group: Administrator
Hero Member
*****

Posts: 2905
It's not as complicated as it may seem...
Thay,

The Fourier component is the peak voltage or current(depending on which is being measured) for that frequency, and the "Normalized" column is the same, but with the fundamental frequency adjusted to the value "1.0" and the harmonics relative to this. You can probably ignore the "normalized" values for your purpose.

Yes, lines 3 and 9 appear to be 50Vp and at 180 degrees.

.99
   
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