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Author Topic: Transformer Induction  (Read 26471 times)

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good stuff O0

now if you can, measure one of the single turns with just the 2 additional cores in place, not connecting all 3 in series. does that bring the single turn down to .33v? 

i like this thread. ;)

mags

its late and im thinking on this.

the reason i ask the above question is, if there is still 30v at the input, 1v per turn, the how does each of the 3 single wires not have 1v each?  does what i ask make sense? has the application of the 3 cores split the E field of the 30 turns into sections of .33v of E field?

so this is a pulse driven input. not ac waveform. could it be that if it is a pulse, is there a time variation of the input pulse for each test?  what im getting at is, the additions of more cores to the 30 turn triangle increases the induction value vs just 1 core i would have to believe. so for the tests of 3 cores vs just 1, i would think the pulse would need to be longer to reach the same max current value as it would the single core test.  or am i missing it. 

im still on the edge with the E field thought train.  sorry.  have been for a long time, im sure you know me by now.  :D lol

here is the gist...  if for each test, 1  core, 2 cores then 3 cores,  the 30 turn coil reaches the same max current for each case, should not the E field in each 30 turn coil section be the same?  or do those cores break that up into sections? thats why i asked above to measure just 1 single wire in 1 single core but with the 2 other cores in place. this is impotant to me and ill conduct my own experiments with you on this here.  just thought since you have it setup, hopefully you could try these things.  im diggin it.

im not interested i what others here have to say on this, for now.  just me and you bud. please enlighten me.  :) 

mags
   

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I would be most interested if PM would use just two ferrite cylinders and connect the two output wires in parallel so they form a closed circuit.  Depending on how they are paralleled they either do nothing or they short out the induced voltages.  For the shorted case the inductance of the series primaries is significantly reduced.  Now put the two output wires across each end of a very long length of 50 ohm coax cable so that the shorting action is delayed.  What do the waveforms look like then?  Initially the two primaries see 50 ohm loads (adjusted by the turns ratio) but later that changes when the time-delayed shorting effect arrives.  I can see some anomalous effects occuring at that instant in time.
   
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its late and im thinking on this.

the reason i ask the above question is, if there is still 30v at the input, 1v per turn, the how does each of the 3 single wires not have 1v each?  does what i ask make sense? has the application of the 3 cores split the E field of the 30 turns into sections of .33v of E field?

so this is a pulse driven input. not ac waveform. could it be that if it is a pulse, is there a time variation of the input pulse for each test?  what im getting at is, the additions of more cores to the 30 turn triangle increases the induction value vs just 1 core i would have to believe. so for the tests of 3 cores vs just 1, i would think the pulse would need to be longer to reach the same max current value as it would the single core test.  or am i missing it. 

im still on the edge with the E field thought train.  sorry.  have been for a long time, im sure you know me by now.  :D lol

here is the gist...  if for each test, 1  core, 2 cores then 3 cores,  the 30 turn coil reaches the same max current for each case, should not the E field in each 30 turn coil section be the same?  or do those cores break that up into sections? thats why i asked above to measure just 1 single wire in 1 single core but with the 2 other cores in place. this is impotant to me and ill conduct my own experiments with you on this here.  just thought since you have it setup, hopefully you could try these things.  im diggin it.

im not interested i what others here have to say on this, for now.  just me and you bud. please enlighten me.  :) 

mags

OK, here is the test result with three cores in place with a measurement taken on only one core's secondary. 

If only two cores are placed on the triangular coil, then each secondary will measure ~.5 volts for a total of ~1 volt.  I will show this in my next post in answer to Smudge's request for two paralleled secondaries.

Pm
   
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I would be most interested if PM would use just two ferrite cylinders and connect the two output wires in parallel so they form a closed circuit.  Depending on how they are paralleled they either do nothing or they short out the induced voltages.  For the shorted case the inductance of the series primaries is significantly reduced.  Now put the two output wires across each end of a very long length of 50 ohm coax cable so that the shorting action is delayed.  What do the waveforms look like then?  Initially the two primaries see 50 ohm loads (adjusted by the turns ratio) but later that changes when the time-delayed shorting effect arrives.  I can see some anomalous effects occuring at that instant in time.

OK, here is the test with two ferrite cores on the triangular coil.  The pix shows the in-phase physical secondary connection only.

The first scope pix Tri Coil Tr4 shows the measurements with the secondaries connected in parallel and in-phase.

The second scope pix Tri Coil Tr4A shows measurements with the secondaries again connected in parallel but out-of-phase.

I'm still looking for a spool of coax cable I thot I had but so far no luck!

Pm 
   

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OK, here is the test result with three cores in place with a measurement taken on only one core's secondary. 

If only two cores are placed on the triangular coil, then each secondary will measure ~.5 volts for a total of ~1 volt.  I will show this in my next post in answer to Smudge's request for two paralleled secondaries.

Pm

so to my question, is it, in your opinion, that the 2 other cores are dividing the E field in the triangle to get that result?  the reason for only testing for the voltage across 1 single wire in the core was to see if it is the other cores alone that are causing that division, and it apears so.  id have to say that if the 30 turns coil were round, we can adjust what we read on that single wire if we move those other  cores closer or further away from the one being read .  does that sound right? 

as it comes to the E field developed along the triangle coil without cores, would that E field be considered 1v??

mags
   
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Mags,

Here is the response from ChatGPT on this subject only I used a round coil instead of a triangular one.

You said:
I have a round 30 turn coil that is 5" in diameter.  I put a 1" pair of ferrite cores over the coil and insert a single turn.  I now apply a 30 volt pulse to the 30 turn coil and I will measure what amount of voltage across the single turn?

ChatGPT said:

If the coupling is reasonably good, you can treat this exactly like a transformer.
Basic transformer relationship
Vs=Vp×NsNp
Vs​=Vp​×Np​Ns​​

Where:

    Vp=30Vp​=30 volts (your applied pulse)

    Np=30Np​=30 turns

    Ns=1Ns​=1 turn

Ideal case
Vs=30×130=1 volt
Vs​=30×301​=1 volt
Realistic case

The actual voltage depends on coupling coefficient kk, which in your geometry may be significantly less than 1, especially because:

    The ferrite cores are only 1" while the coil is 5" diameter → not fully linking the field

    The single-turn loop may not tightly couple to all flux

    Pulse rise time matters (leakage inductance)

In practice:
Vs≈k×1 V
Vs​≈k×1 V

Typical kk for such a poorly-fitting geometry might be 0.1 to 0.5, so the observed voltage could be something like:

0.1–1.0 volt
If the single turn is placed entirely inside the closed ferrite core

…and the 30-turn coil’s flux fully passes through that core, then kk could approach 1, and you would indeed see very close to 1 volt.

If you want, tell me how the ferrite cores are arranged over the coil (e.g., clamshell? does it close fully around the conductor?) and I can estimate a more accurate coupling coefficient and real output voltage.
You said:

OK, now if I place an additional ferrite core set on the same 30 turn coil, how will this affect the single turn measurement on the first ferrite core?

ChatGPT said:

Short answer: The voltage on the first single-turn will stay almost the same, unless the second ferrite core significantly diverts flux away from the first one.

But let’s explain why.
✔ What happens when you add a second ferrite core set to the same 30-turn coil?

You now have something like this:

    One 30-turn primary coil

    Two separate ferrite cores placed around different parts of the coil

    Each core may contain its own secondary winding (your single turn)

This behaves like a transformer with multiple secondaries, except that the magnetic paths are not shared—they are local to each ferrite core.
Key Principle

The voltage induced in a secondary is proportional to the local magnetic flux through that core:
Vs=NsdΦdt
Vs​=Ns​dtdΦ​

Adding another ferrite core simply creates another local flux path, but it does not steal flux from the first core unless the coil’s field is “flux-limited.”
✔ What actually changes?
Case 1 — The ferrite cores are far enough apart and not interacting

Each core sees roughly the same field generated by the 30-turn coil.

    The first core still sees nearly the same flux as before

    The induced voltage in the first single-turn stays the same

    The second core also produces its own induced voltage (also ~1 V ideal)

This is the most common situation.
Case 2 — The cores are very close together so that their flux paths compete

This is uncommon but possible if:

    They are touching or nearly touching

    Their magnetic circuits strongly interact

    The ferrite partially saturates (unlikely with 30 V pulse unless pulse is long)

In this case, the effective permeance of the system changes, and the flux divides between the cores. However, even then:

    The first core might see slightly less flux

    The reduction is usually small unless the ferrite saturates

✔ Practical conclusion
Adding a second ferrite core will NOT significantly change the induced voltage in the first single turn.

You will still measure approximately:
Vs1≈3030=1 V×k1
Vs1​≈3030​=1 V×k1​

where k1k1​ is the coupling coefficient to the first core.

The second ferrite core will produce:
Vs2≈1 V×k2
Vs2​≈1 V×k2​

Both voltages exist independently.
✔ Exception: If your pulse is long and the ferrite saturates

Then inductance drops, current rises, flux changes, and both secondary voltages may fall as the ferrite saturates.

If you tell me:

    Pulse duration

    Pulse rise time

    Ferrite material type (e.g., 3C90, N87, etc.)

    Coil current

    Placement of cores

…I can calculate whether saturation is possible and estimate the exact performance.


So, we seemingly have a dilemma!

Pm

Edit: Actually there is no dilemma as each added core reduces the triangular coil's current and thus the flux which in turn reduces the E-Field in each added core section.
   

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ok.   not an actual answer to some of my questions, but its a start..

firstly, it didnt provide any E field in the mix, only flux.  so as you know im a firm believer in faraday flux cutting vs E field theory. so the ai pivots toward my beliefs so far.

on your triangle with 3 cores and only one with a wire being tested for voltage, does the voltage in the test change if you slide the other 2 cores say closer  to the 30v input corner and then slide them closer to the 2 corners of the angle with the core and single wire being tested?  all to see if the division changes.  if not then i think the cores are just increasing inductance and we are not reaching same max current for each case.

i initially was thinking what the ai said that you would still get 1v from the single test wire when you applied the other 2 cores. and then it said that the pulse length would need to be different with the added cores. 

if the ai did claim 1v still, then it is saying what i said before that the addition of the other 2 cores increases the inductance of the triangle/circle 30 turn winding, in which i believe you will need to change the pulse width of your input in order for each case to reach max current, same max current for each case, in order for the test to qualify accuracy in each case.  so for example, i see in your scope shots different currents on the scope for each case you have shown. i think that needs to be addressed in order to qualify fair tesing here.   

hopefully that makes sense. hate to be repetitive, but i need what im saying to sink in..

mags
   

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also, we are not loading the test wire in any significant way. so reading that wire should not alter the functions of the whole to affect anything as the ai alluded to if it were loaded.

mags
   
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I would like to take a guess on the separate ferrite cores and lower voltage.  Don't worry, Your thread, not here to argue :)

My guess is,  each extra ferrite cores added changes the reluctance in the primary magnetic path. As we decrease reluctance, the primary behaves with more and more reactance.

Usually lowering reluctance should result in more voltage output from a condensed field within the core, but the separate cores play a role, resulting in each separate core seeing less push from the primary because the choke effect is creeping in more and more as you add cores.

I bet if an inductance meter was used, you would witness the triangle getting more and more inductive every core that you add.

Just my guess

Edit-  OOps I missed your last line..  "Edit: Actually there is no dilemma as each added core reduces the triangular coil's current and thus the flux which in turn reduces the E-Field in each added core section."   I guess it was already explained


---------------------------
Jim Mac - Owner of Mooker.Com Opensource Free Energy Forum
   
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Mags,

The first scope pix below Tri Coil Tr5 is a test where the triangular coil has three sets of ferrite cores in place with the pulse frequency is lowered to achieve a peak coil current of 150ma.  The voltage across a single secondary is now seen to be 352mv.

If the other two ferrite cores are moved closer to or away from the active core, no change is seen.

Tri Coil Tr6 is a measurement of all three secondaries connected is series.

Pm
   

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here is a pdf that discusses what you are showing.  the second to the last depiction is the same, but reversed in and out.

mags
   

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OK, here is the test with two ferrite cores on the triangular coil.  The pix shows the in-phase physical secondary connection only.

The first scope pix Tri Coil Tr4 shows the measurements with the secondaries connected in parallel and in-phase.

The second scope pix Tri Coil Tr4A shows measurements with the secondaries again connected in parallel but out-of-phase.

I'm still looking for a spool of coax cable I thot I had but so far no luck!

Pm
Thanks for doing that.  Clearly the input inductance has reduced for the second case as expected.  I think the reduction would be geater if each ferrite had more than a 1 turn secondary.  I have amended my paper on transformers connected to a delay line to make things clearer, attached here.  It is that sudden drop in flux that occurs after the delay and how it returns energy to the source that is of interest here for this two transformers case.  Does it really happen?

Smudge
   
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here is a pdf that discusses what you are showing.  the second to the last depiction is the same, but reversed in and out.

mags

I had not seen that pdf before so thanks for sharing!  It is exactly what I've been researching lately only I've used the basis of E-Field charge separation instead of core flux.  Results are the same.

In the first pix below we see the physical setup that produced the following scope trace pix.  Two identical toroid cores are physically connected together with a 12 turn winding and then each toroid receives an additional 12 turn winding as shown. 

The two outside windings are connected in a series bucking mode and then a 24 volt peak pulse is applied.  The center winding is the secondary.

The CH1(yel) trace is the input pulse to a 3/4 bridge drive circuit, CH2(blu) is the power supply, CH3(pnk) is the open circuit output across the secondary, and CH4(grn) is the primary current.  Math(red) can be ignored

This configuration is basically the same as the last figure you show in the pdf only with two cores instead of three.

Here we see a primary consisting of 24 total turns that is supplied with a 24 volt pulse that is producing a 24 volt output pulse across 12 turns.  This is certainly not normal transformer action.  My explanation using the E-Field is that the primary voltage is split between the two primary windings with each having 12 volts applied.  The coupling between these two primary windings is very low so we have the secondary winding subjected to two out-of-phase 12 volt E-Fields in each core window.  These E-Fields therefore add in the 12 turn secondary to equal 24 volts.  All voltage levels are approximate for clarity.

The primary and secondary inductances will be nearly equal but this is for another discussion.

Pm

   
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Thanks for doing that.  Clearly the input inductance has reduced for the second case as expected.  I think the reduction would be geater if each ferrite had more than a 1 turn secondary.  I have amended my paper on transformers connected to a delay line to make things clearer, attached here.  It is that sudden drop in flux that occurs after the delay and how it returns energy to the source that is of interest here for this two transformers case.  Does it really happen?

Smudge

You're welcome.  I agree that more secondary turns would result in a greater inductance reduction.

I think I might be able to simulate your delay line circuit if you can give an idea of how much delay to start with.

Pm
   

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here is another pdf that explains how flux propagates through a toroid core transformer.  it follows what i believe it to be..  im a flux guy.   ;)

it is a compliment to the last pdf i uploaded.  ill post both here.

Mags
   

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Thanks for doing that.  Clearly the input inductance has reduced for the second case as expected.  I think the reduction would be geater if each ferrite had more than a 1 turn secondary.  I have amended my paper on transformers connected to a delay line to make things clearer, attached here.  It is that sudden drop in flux that occurs after the delay and how it returns energy to the source that is of interest here for this two transformers case.  Does it really happen?

Smudge
In that paper I show that plotting primary current against flux can show the two diiferent energies, load current energy and magnetizing current energy, as inputs.  What I failed to do was show that plotting secondary current against flux shows that transfer of energy to the load as an output.  Below I correct that combining the two currents onto one chart where the red areas are input and the green areas are output.  The second chart is the case where the secondary current jumps from 1A to 2A and during that jump the flux reduces down to zero.  Taking the rectangle areas as 1 unit of energy it is now clear that before that secondary jump the primary input is 1.5 units of energy where 1 unit has passed through the transformer to be stored in the delay-line and 0.5 units is lost to the core.  If we then disconnect the delay line and immediately replace it with a current source that ramps up from 1A to 2A we get the situation shown in the second chart.  That current generator pumps in 1.5 units of energy and if we somehow used the 1 unit stored in the delay line the total energy input so far is 1.5+0.5=2 units.  The pumping action causes the primary to return 2 units of energy to its source so there is no OU.

Smudge
   
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In that paper I show that plotting primary current against flux can show the two diiferent energies, load current energy and magnetizing current energy, as inputs.  What I failed to do was show that plotting secondary current against flux shows that transfer of energy to the load as an output.  Below I correct that combining the two currents onto one chart where the red areas are input and the green areas are output.  The second chart is the case where the secondary current jumps from 1A to 2A and during that jump the flux reduces down to zero.  Taking the rectangle areas as 1 unit of energy it is now clear that before that secondary jump the primary input is 1.5 units of energy where 1 unit has passed through the transformer to be stored in the delay-line and 0.5 units is lost to the core.  If we then disconnect the delay line and immediately replace it with a current source that ramps up from 1A to 2A we get the situation shown in the second chart.  That current generator pumps in 1.5 units of energy and if we somehow used the 1 unit stored in the delay line the total energy input so far is 1.5+0.5=2 units.  The pumping action causes the primary to return 2 units of energy to its source so there is no OU.

Smudge

Thanks for this update!  I have already attempted to simulate this core topology with a delay line but was not successful.  LtSpice can not and will not create a usable matrix with the 'k' factors or coupling factors of the actual core assembly and thus gives an error message saying basically that the core model is impossible.  I'm not sure if using capacitor/gyrator modeling could yield a workable solution but it seems that you have answered the question of whether this idea could yield OU so I won't attempt a solution.

Pm
   

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here is pics of what im going for.
each core will have 20 turns 30awg and all 8 will be in series.
once they are done ill mount them on a plexy square as shown below using small spacers. this arrangement will make for simple threading of the secodary through all 8 cores. being the sec will be longer for each turn, im using 26awg to reduce its resistance.  going to make 3 separate sec windings of 10 turns each for ease of trying 1 winding as an output or up to all 30 turns in series.

the pdf uses ac but im going to try pulsing first. should have the transformer together tomorrow.

mags
   

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What I failed to do was show that plotting secondary current against flux shows that transfer of energy to the load as an output.
I told you so.
   
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Just FYI. 

It appears to me in my continued testing of charge separation in various cores, that the E-Field magnitude is dependent on the amount of flux retained in the core material.  IOW, any leakage flux outside the core creates a loss in the E-Field within the core window and attributes to the apparent E-Field outside the core.  As a core saturates for example, more flux leaves the core and also creates a reduction in the measured E-Field within the core window.

Therefore IMO, a lossless core relative to it's flux magnitude, would result in zero E-Field outside the core.

Pm
   

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Below are the mental gymnastics that I have to perform in order to understand the statement:

It appears to me in my continued testing of charge separation in various cores, that the E-Field magnitude is dependent on the amount of flux retained in the core material.
The word "retained" suggests something that remains after being kept.  It is not far form there to the magnetic remanence and associated hysteresis losses.
But somehow I have doubts that the author has the BH curve and magnetic remanence in mind.

IOW, any leakage flux outside the core...
"leakage flux" suggests an issue with flux confinement and the Hopkinson's law.

As a core saturates for example, more flux leaves the core...
Yes, ferromagnetic saturation decreases the differential permeability, increases the associated reluctance and causes flux leakage ...so the focus is on flux confinement in the core - not on the ferromagnetic remanence.

Therefore IMO, a lossless core relative to it's flux magnitude, would result in zero E-Field outside the core.
Considering the above, the phrase "lossless core" does not refer to a core that has no hysteresis losses.
Rather the focus is on the flux confinement within the core and the flux distribution according to Hopkinson's law in a system where the reluctance of core's path increases with its saturation wrt to the reluctance of paths outside of the core.
   

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Just FYI. 

It appears to me in my continued testing of charge separation in various cores, that the E-Field magnitude is dependent on the amount of flux retained in the core material.  IOW, any leakage flux outside the core creates a loss in the E-Field within the core window and attributes to the apparent E-Field outside the core.  As a core saturates for example, more flux leaves the core and also creates a reduction in the measured E-Field within the core window.

Therefore IMO, a lossless core relative to it's flux magnitude, would result in zero E-Field outside the core.

Pm

I disagree.  The image below shows the E field around a lossless core where the length of the arrows depict the field strength.  There is no sudden change to zero field going from "inside the core" position to outside the core.

Smudge 
« Last Edit: 2025-12-19, 08:37:06 by Smudge »
   
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Magluvin

Nice set of cores. Maybe suitable for this experiment ? https://www.youtube.com/watch?v=Dz0GUqxCPp4
How about parallel resonant tank circuit on primary ? Should it matter ?
   

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The image below shows the E field around a lossless core where the length of the arrows depict the field strength.  There is no sudden change to zero field going from "inside the core" position to outside the core.
...and a couple of words about its loop integral, please.
   
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Below are the mental gymnastics that I have to perform in order to understand the statement:

The word "retained" suggests something that remains after being kept.  It is not far form there to the magnetic remanence and associated hysteresis losses.
But somehow I have doubts that you have the BH curve and magnetic remanence in mind.

Yes, 'retained' is not the best choice of words here just simply the 'magnitude' of flux!  The BH curve and remanence are not in consideration because we can determine results from a single unipolar pulse without any field collapse.

Quote
"leakage flux" suggests an issue with flux confinement and the Hopkinson's law.

Not being familiar with the complex (to me) Hopkinson's law, the simple answer is a matter of flux confinement that is, flux contained within a core verses flux outside that same core at any given time.

Quote
Yes, ferromagnetic saturation decreases the differential permeability, increases the associated reluctance and causes flux leakage ...so the focus is on flux confinement in the core - not on the ferromagnetic remanence.

Yes that is correct!

Quote
Considering the above, the phrase "lossless core" does not refer to a core that has no hysteresis losses.
Rather the focus is on the flux confinement within the core and the flux distribution according to Hopkinson's law in a system where the reluctance of core's path increases with its saturation wrt to the reluctance of paths outside of the core.

Again, a poor choice of words on my part and yes, you are correct.

Pm 
   
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