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Hi Itsu,
Thanks for these. I assume the generator voltage across the 120 Ohm emitter resistor is pretty close to 526 mVpp. Generally, emitter followers has a 'gain' of 0.9- 0.95, but this 'improve' the calculated Q only a little. Unfortunately, a much higher emitter current would be needed to reduce the virtual emitter resistance. If we choose say IE = 1 Amper emitter current, the 26 mV / IE gives 0.026 Ohm, this is much less than the coils DC resistance of 0.1 Ohm. This would need say a RE = 10 Ohm and >10 W power rated resistor and a 2N3055 or similar transistor, R1 would be say 1 kOhm. IF you agree and assign the time, maybe we can get a more correct Q value. (IF the power transistor has a low hFE value, use a small transistor in Darlington connection to the power transistor, R1 would be say 100 kOhm in this case to bias the base of the small transistor.)
Gyula
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