The real losses are insane, a 2000' #14 conductor running at 120v/10A (1200w) losses near 42% of it's power or 505 watts. Where the same conductor running at 30kV/40 mA (1200w) only losses 0.00067% of it's power or 0.00808 watts. This is why most FE inventors were converting the input to high voltage levels. The input could be 12v but the working circuit was generally always HV.
being into car audio for 30+ yrs, just an increase from 12v to 16v supply, the advantages are there. Soundstream back in their car audio beginnings, the amplifier and power supply were separate units. the power supply was mounted close to the battery and only the +/- rail voltages were sent to the amp. so instead of running heavy wire 12v back to a conventional amp, they ran rails of 25v +/- with lower gauge wire. and to another point, back then, the switching power supplies were not even up to 20khz. so that separation of the supply and amp was multi purpose. but since we are here, lets take that 2000' and coil it. which will produce the most magnetic field/flux, 120v/10a or 30kv/40ma? OR, are we chatting about something else? seems to be this is about source to load efficiencies through 2000' of 14awg. of which for each V/A condition given, 120v/30kv, the loads would need to be 12ohm/750kohm including the resistance of the 2000' wire. does it give us any guidance on the plunger project? mags
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Topic: The 2026 solenoid plunger competition (Read 1324 times)
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