I would like to explain my perspective on what I call "transposition" of a voltage source using charge separation in the E-Field of a closed flux core arrangement, ie a toroid. For one example of transposing a voltage source, I refer to my Li-on charging experiment here. Like transposing a chord in a musical scale, a voltage source can be transposed in the E-Field via a charge separation potential gradient. This comes with certain advantages in the FE pursuit. Here, I will show the transposition of a charged capacitor placed in the core of a toroid and subjected to this charge separation. First we see the schematic of the circuit. Here we see C1 pre-charged to 4 volts thru R1 with a 20 ohm load connected thru D2 to the mosfet switch M1. The M1 gate drive is synchronized with V1 such that the 20 ohm load is only connected when a positive voltage of 48v is applied to L1 for the first half cycle. During the second half cycle when the energy accumulated in L1 is returned to the 48v supply V1, M1 is not conducting. We will ignore these input energy levels in L1 for the time being. With the supply of 48v DC and 12 turns in L1, we will be applying ~4v/turn to the primary L1. We will then expect to see the voltage on C1 to increase ~4v with the positive pulse applied to L1. Scope 'Cap Trans1' shows the voltage increase across C1 to ~7.9v and we also see a decrease in the voltage across C1 down to 6.72v due to the load current in R1. We also see the the mean current thru R1 to be 324.6ma over 12.09us for an energy level of .3246^2*20*12.09e-6=25.5uJ. The apparent loss in C1 is (7.92^2-6.72^2)*4e-6/2=35.1uJ. 'Cap Trans2' shows the starting voltage across C1 to be 3.88v and ending voltage to be 2.88v. This results in an actual energy loss in C1 to be (3.88^2-2.88^2)*4e-6/2=13.5uJ. The difference in energy levels in C1 is made up in the input energies so no free lunch at this point in time. However, if we can discharge a transposed voltage source with these results, what will be the result if we charge a transposed voltage source? Also, when the voltage across L1 is negative and we see the positive terminal of C1 negative, the voltage internal to C1 on the grounded plate is ~4v more negative than the positive terminal (same as in the Li-on experiment) and is most important when considering the RLE circuit requirements. Pm
« Last Edit: 2026-02-15, 17:39:45 by partzman »
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